Level 493 · High Culture · 15 clues

Figgerits Level 493 Answers

"Painting the Mona Lisa’s lips took Leonardo da Vinci twelve years" — all 15 clues solved below.

Looking for Figgerits Level answers? This page has the complete verified clue list for every puzzle. All answers are free — no sign-up or account needed. Use the navigation to jump to any nearby level. Figgerits is a unique mobile logic puzzle game that combines word-finding with cryptogram-style decoding. Each level presents a series of clues where you solve individual words and then use the numbered letters to decode a hidden phrase or quote. The mix of vocabulary skill and logical deduction makes Figgerits stand out. This guide provides complete verified answers for every Figgerits level and pack.

Hidden Phrase

"Painting the Mona Lisa’s lips took Leonardo da Vinci twelve years"

All 15 Clues & Answers

Double
TWICE
Person working in advertising
ADMAN
Incarnation of a deity in Hinduism
AVATAR
Film tape is wound around a ___
SPOOL
The football team's ___ is a bull
MASCOT
Parody, satire, caricature
LAMPOON
Pub or bar where beer is served
TAPROOM
Feudal ruler, someone with authority over others
OVERLORD
The cost of this project is rising at an ___ rate
ALARMING
Cushion for kneeling during prayer
HASSOCK
Phone service providing some form of assistance
HELPLINE
Populism
DEMAGOGY
In retrospect, his warning was incredibly ___
PRESCIENT
Pioneer, trailblazer, inventor
INNOVATOR
Lasting for a very long time
PERENNIAL

Nearby Levels

Figgerits Level 493 — FAQ

What pack is Level 493 in?

Level 493 is in the High Culture pack.

How many clues does Level 493 have?

Level 493 has 15 clues to solve.

What is the hidden phrase in Level 493?

The hidden phrase is: "Painting the Mona Lisa’s lips took Leonardo da Vinci twelve years"

Is Figgerits free?

Yes — Figgerits is free to download on iOS and Android. This site is also completely free.

How do I navigate between Figgerits levels?

Use the Previous and Next arrows at the bottom of this page, or return home to jump to any level by number.